\(\Delta=\left[-2\left(m-2\right)\right]^2-4\left(m-4\right)\left(m-1\right)=4m\)
\(\Rightarrow x_1=\frac{2\left(m-2\right)+\sqrt{4m}}{2\left(m-4\right)};x_2=\frac{2\left(m-2\right)-\sqrt{4m}}{2\left(m-4\right)}\)
\(\Rightarrow x_1.x_2=2m-2\)
Ta có: \(\Delta\ge0\Leftrightarrow4m\ge0\Leftrightarrow m\ge0\)
Mà \(m>0\Rightarrow m\ge1\)
GTNN của \(m\) là \(1\)
Vậy \(m=1\)