Ta có: AB//CD(ABCD là hthang cân)
\(\Rightarrow\widehat{B}+\widehat{C}=180^0\Rightarrow\widehat{B}=180^0-\widehat{C}=180^0-100^0=80^0\)
Ta có: ABCD là hthang cân
\(\Rightarrow\left\{{}\begin{matrix}\widehat{A}=\widehat{B}=80^0\\\widehat{C}=\widehat{D}=100^0\end{matrix}\right.\)