Question

cho g(x)= 4x^4+3x+1

 h(x)=3x^2-2x-3. Tính f(x)=g(x)-h(x)

Answer 1

f(x)=g(x)-h(x)=4x⁴+3x+1-3x²+2x+3

=4x⁴-3x²+5x+4

Answer 2

\(f\left(x\right)=4x^4+3x-1-\left(3x^2-2x-3\right)=4x^4-3x^2+5x+2\)

Answer 3

ta có 

góc HAD+ góc CAK=180*-BAC=180*-90*=90* 

góc CAK+ góc ACK=180*-90*=90*

=> góc HAD=góc ACK

xét 2 tam giác vuông AHB và CKA có:

AB=AC(gt)

góc HAD=góc ACK(cmt)

=> tam giác AHB=tam giác CKA(CH-GN)

=> AH=CK(đfcm)

b) theo câu a, ta có tam giác AHB=tam giác CKA(CH-GN)

=> AK=BH

ta có: HK=AH+AK=CK+BH(đfcm)

Answer 4

\(f(x)=(4x^4+3x+1)-(3x^2-2x-3)\)

\(f(x)=4x^4+3x+1-3x^2+2x+3\)

\(f(x)= 4x^4-3x^2+5x+4\)