h(x)=f(x)-g(x)= 5x^3+3x^2-9x+1-4x3+7x3+6x+16
=8x3+3x2-3x+17
Ta có: \(f\left(x\right)=5x^3+3x^2-9x+1\)
\(g\left(x\right)=4x^3-7x^3-6x-16\)
\(h\left(x\right)=f\left(x\right)-g\left(x\right)=\left(5x^3+3x^2-9x+1\right)-\left(4x^3-7x^3-6x-16\right)\)
\(=5x^3+3x^2-9x+1-4x^3+7x^3+6x+16\)
\(=8x^3+3x^2-3x+17\)
f(x)-g(x)=h(x)
f(x)-g(x)=5x3+3x2-9x+1-(4x3-7x3-6x-16)
f(x)-g(x)=5x3+3x2-9x+1-4x3+7x3+6x+16
f(x)-g(x)=5x3-4x3+7x3+3x2+6x-9x+1+16
f(x)-g(x)=8x3+3x2-3x+17
Vậy h(x)=8x3+3x2-3x+17
h(x)=8x^3+3x^2-3x+17
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