\(a\left(b+c\right)+b\left(c+d\right)+d\left(c+a\right)\)
\(=ab+ac+bc+bd+dc+da\)
Áp dụng BĐT AM-GM ta có:
\(a\left(b+c\right)+b\left(c+d\right)+d\left(c+a\right)\ge6.\sqrt[6]{ab.ac.bc.bd.cd.ad}=6\sqrt[6]{a^3b^3c^3d^3}=6.\sqrt[6]{1}=6\)Dấu " = " xảy ra <=> a=b=c=d=1