\(\dfrac{1+7y}{7x}=\dfrac{1+9y}{2x}\Rightarrow\dfrac{2+14y}{14x}=\dfrac{7+63y}{14x}\)
\(\Rightarrow2+14y=7+63y\Rightarrow49y=-5\Rightarrow y=\dfrac{-5}{49}\)
\(\Rightarrow\dfrac{1+5\left(\dfrac{-5}{49}\right)}{24}=\dfrac{1+7\left(\dfrac{-5}{49}\right)}{7x}\)
\(\Rightarrow\dfrac{1}{49}=\dfrac{2}{49x}\Rightarrow x=2\)
Vậy \(\left\{{}\begin{matrix}x=2\\y=\dfrac{-5}{49}\end{matrix}\right.\)