a: \(\Leftrightarrow\sqrt{x-3}\left(\sqrt{x+3}-\sqrt{2x}\right)=0\)
=>2x=x+3 hoặc x-3=0
=>x=3
b: \(=2\sqrt{x-5}+\sqrt{x-5}-\dfrac{1}{3}\cdot3\sqrt{x-5}=2\sqrt{x-5}\)
a. ĐKXĐ: \(\left\{{}\begin{matrix}-3\le x\le3\\0\le x\le3\end{matrix}\right.\)\(\Rightarrow0\le x\le3\)
\(\sqrt{x^2-9}-\sqrt{2x^2-6x}=0\)
\(\Leftrightarrow\sqrt{x^2-9}=\sqrt{2x^2-6x}\)
Bình phương hai vế ta được:
\(x^2-9=2x^2-6x\) \(\Leftrightarrow x^2-6x+9=0\)\(\Leftrightarrow x=3\left(TM\right)\)