Question

Các bạn ơi hãy giúp mik biện luận pt dưới đây theo tham số m với. Cảm ơn rất nhiều!

\(\frac{x+m+1}{x+m}-\frac{x+11}{x+10}=\frac{10}{\left(x+m\right)\left(x+10\right)}\)

Ai đúng mik tick cho nhé !

Answer 1

\(\frac{x+m+1}{x+m}-\frac{x+11}{x+10}=\frac{10}{\left(x+m\right)\left(x+10\right)}\)

ĐKXĐ: \(x\ne-10\)

➝\(\frac{\left(x+m+1\right)\left(x+10\right)}{\left(x+m\right)\left(x+10\right)}-\frac{\left(x+11\right)\left(x+m\right)}{\left(x+10\right)\left(x+m\right)}=\frac{10}{\left(x+m\right)\left(x+10\right)}\)

➝\(\left(x+m+1\right)\left(x+10\right)-\left(x+11\right)\left(x+m\right)=10\)

Nhân vào, xong thay "m" vào rồi tính!!

Answer 2

Có: \(\left(x+m+1\right)\left(x+10\right)-\left(x+m\right)\left(x+11\right)=10\)

\(\Leftrightarrow\left(x+m\right)\left(x+10\right)+\left(x+10\right)-\left(x+m\right)\left(x+11\right)=10\)

\(\Leftrightarrow\left(x+m\right)\left(x+10-x-11\right)+x=0\)

\(\Leftrightarrow-x+m+x=0\)

\(\Leftrightarrow m=0\)