x=-0,3y
nên y=-10/3x
Ta có: y=1/2z
nên \(\dfrac{-10}{3}x=\dfrac{1}{2}z\)
\(\Leftrightarrow x=z\cdot\dfrac{1}{2}:\dfrac{-10}{3}=z\cdot\dfrac{1}{2}\cdot\dfrac{-3}{10}=z\cdot\dfrac{-3}{20}\)
a: Khi z=3 thì x=-9/20
Khi z=-2/3 thì \(x=\dfrac{2}{3}\cdot\dfrac{3}{20}=\dfrac{1}{10}\)
Khi z=1/4 thì \(x=\dfrac{-3}{20}\cdot\dfrac{1}{4}=\dfrac{-3}{80}\)