a: \(1+\tan^2a=\dfrac{1}{\cos^2a}\)
nên \(\dfrac{1}{\cos^2a}=\dfrac{169}{144}\)
\(\Leftrightarrow\cos a=\dfrac{12}{13}\)
=>\(\sin a=\dfrac{5}{13}\)
b: \(\sin a=\sqrt{1-0.4^2}=\dfrac{\sqrt{21}}{5}\)
\(\tan a=\dfrac{\sqrt{21}}{2}\)
\(\cot a=\dfrac{2\sqrt{21}}{21}\)