Question

Bài 1: Phân tích các đa thức thành nhân tử
 1. 4𝑥 2 – 6x
2. –28𝑥 2𝑦 5 – 14𝑥 3𝑦 4 – 21𝑦 3
3. 4x(a – b) + 6xy(b – a)
 4. (6x + 3) – (2x – 5)(2x + 1)
5. 4(𝑥 − 3) 2 + 2x(3 – x)
6. 𝑥 4 + 2𝑥 3 – 4x – 4 7. 2x(x + y) – x – y
8. (3𝑥 − 1) 2 – (𝑥 + 3) 2 
đều có số mũ hết nha, giúp dùm tui vs

Answer 1

1,\(=4x\left(x-\dfrac{3}{2}\right)\)
2,\(=-7y^3\left[2x^2y\left(2y+x\right)+3\right]\)
3, = 4x(a-b)-6xy(a-b)
=2x(a-b)(2-3y)
4,
=3(2x+1)-(2x-5)(2x+1)
=(3-2x+5)(2x+1)
=(8-2x)(2x+1)
=2(4-x)(2x+1)
 

Answer 2

5: \(4\left(x-3\right)^2+2x\left(3-x\right)\)

\(=\left(x-3\right)\left(4x-12\right)-2x\left(x-3\right)\)

\(=\left(x-3\right)\left(2x-12\right)\)

\(=2\left(x-6\right)\left(x-3\right)\)

8: \(\left(3x-1\right)^2-\left(x+3\right)^2\)

\(=\left(3x-1-x-3\right)\left(3x-1+x+3\right)\)

\(=\left(2x-4\right)\left(4x+2\right)\)

\(=4\left(x-2\right)\left(2x+1\right)\)