a: AB=5cm
P=(5+5+6)/2=16/2=8cm
\(S=\sqrt{8\cdot\left(8-6\right)\left(8-5\right)\left(8-5\right)}=\sqrt{8\cdot2\cdot3\cdot3}=4\cdot3=12\left(cm^2\right)\)
b: Kẻ CH vuông góc với AB
\(\dfrac{S_{CDA}}{S_{CDB}}=\dfrac{CH\cdot DA}{2}:\dfrac{CH\cdot DB}{2}=\dfrac{DA}{DB}\)