Question

A) (x-2)^2=1/16

B) (x-1)^2=(1-x)^4

C) (3x-1/5)^2=(2/3)^6

Đ) 3x/27=3^-1

Answer 1

A) \(\left(x-2\right)^2=\dfrac{1}{16}\\ Mà:\left(\dfrac{1}{4}\right)^2=\dfrac{1}{16}hoặc\left(-\dfrac{1}{4}\right)^2=16\\ =>\left(x-2\right)^2=\left(\dfrac{1}{4}\right)^2hoặc\left(x-2\right)^2=\left(-\dfrac{1}{4}\right)^2\\ =>x-2=\dfrac{1}{4}hoặc\left(x-2\right)=-\dfrac{1}{4}\\ =>\left[{}\begin{matrix}x=\dfrac{1}{4}+2\\x=-\dfrac{1}{4}+2\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=\dfrac{9}{4}\\x=\dfrac{7}{4}\end{matrix}\right.\)