Question

a. \(\sqrt{x}\left(\sqrt{x}-3\right)-5\left(\sqrt{x}+3\right)\)

b. \(3\left(2+\sqrt{x}\right)+\left(\sqrt{x}+3\right)\left(2-\sqrt{x}\right)\)

c. \(\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)-5\left(\sqrt{x}-1\right)\)

d. \(3\left(\sqrt{x}-2\right)-\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)\)

Answer 1

Answer 2

a: Ta có: \(\sqrt{x}\left(\sqrt{x}-3\right)-5\left(\sqrt{x}+3\right)\)

\(=x-3\sqrt{x}-5\sqrt{x}-15\)

\(=x-8\sqrt{x}-15\)

b: Ta có: \(3\left(\sqrt{x}+2\right)+\left(\sqrt{x}+3\right)\left(2-\sqrt{x}\right)\)

\(=3\sqrt{x}+6+2\sqrt{x}-x+6-3\sqrt{x}\)

\(=-x+2\sqrt{x}+12\)

c: Ta có: \(\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)-5\left(\sqrt{x}-1\right)\)

\(=x-9-5\sqrt{x}+5\)

\(=x-5\sqrt{x}-4\)

d: Ta có: \(3\left(\sqrt{x}-2\right)-\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)\)

\(=3\sqrt{x}-6-x+1\)

\(=-x+3\sqrt{x}-5\)