\(8^x:4^x=16\)
\(\Leftrightarrow2^{3x}:2^{2x}=2^4\)
\(\Leftrightarrow2^{3x-2x}=2^4\)
\(\Leftrightarrow3x-2x=4\)
\(\Leftrightarrow x=4\)
Vậy ..
\(8^x:4^x=16\)
\(\left(8:4\right)^x=16\)
\(2^x=16\)
=> x = 4
\(\dfrac{8^x}{4^x}=16\Rightarrow\left(\dfrac{8}{4}\right)^x=2^4\Rightarrow2^x=2^4\Rightarrow x=4\)