\(\left(\dfrac{4}{3}\right)^{5x}.\left(\dfrac{3}{16}\right)^{5x}=0\)
\(\left(\dfrac{4}{3}.\dfrac{3}{16}\right)^{5x}=0\)
\(\left(\dfrac{1}{4}\right)^{5x}=0\)
⇔\(\dfrac{1}{4}=0\) (vô lí)
⇒không tồn tại x
1: Tính : \(\dfrac{\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7.5^2+512}\) 2 . Tìm x biết :\(\left(5.x+1\right)^2=\dfrac{36}{49}\)
1 Tìm x biết :
a) \(\left(5x+1\right)^2\) = \(\dfrac{36}{49}\)
b) \(\left(x-\dfrac{2}{9}\right)^3\) = \(\left(\dfrac{2}{3}\right)^6\)
c) \(\left(8x-1\right)^{2n+1}\) = \(5^{2n+1}\) \(\left(n\in N\right)\)
tìm x biết
a) \(\dfrac{2}{5}-\left(\dfrac{1}{10}-x\right)=\left(\dfrac{-2}{5}-\dfrac{1}{2}\right)^2\)
b) \(\dfrac{2}{5}-\dfrac{3}{5}\left(x-2\right)=\left(\dfrac{-1}{2}\right)^3-\left(\dfrac{3}{4}\right)^3.\left(-2\right)^2\)
tim x
a, \(\left(3x-2\right)^2=16\)
b, \(\left(\dfrac{4}{5}x-\dfrac{3}{4}\right)^3=\dfrac{-8}{125}\)
c, \(5^{x+2}+5^x=3250\)
d, \(\left(4x-3\right)^4=\left(4x-3\right)^2\)
giup minh nhe minh dang can gap
bài 1: thực hiện phép tính
a)\(\dfrac{2^5.8^4.4^3}{16^6}\)
b) \(\left(\dfrac{3}{5}-\dfrac{3}{4}\right).\left(\dfrac{2}{6}-\dfrac{1}{5}\right)^2\)
c)\(3.[\dfrac{-2}{5}]-\left(\dfrac{-1}{2}\right).4:\left(\dfrac{-1}{2}\right)^2\)
BT4:Tìm x, biết:
a) \(x\div\left(\dfrac{3}{4}\right)^3=\left(\dfrac{3}{4}\right)^2\)
b) \(\left(\dfrac{2}{5}\right)^5\div x=\left(\dfrac{2}{5}\right)^8\)
\(15x\left(-\dfrac{2}{3}\right)^2-\dfrac{7}{4}x\left(-\dfrac{2}{3}\right)^2\)
Rút gọn biểu thức:
P = \(\dfrac{1}{3}\) - \(\left(\dfrac{1}{3}\right)^2\) + \(\left(\dfrac{1}{3}\right)^3\) - \(\left(\dfrac{1}{3}\right)^4\) + ... + \(\left(\dfrac{1}{3}\right)^{19}\) - \(\left(\dfrac{1}{3}\right)^{20}\)
mọi người ơi giúp mik với ai làm đc mik tick cho
Tìm x, biết:
a) x : \(\left(\dfrac{3}{4}\right)^3\)= \(\left(\dfrac{3}{4}\right)^2\) b) \(\left(\dfrac{2}{5}\right)^5\). x = \(\left(\dfrac{2}{5}\right)^8\)
