a) \(\dfrac{2}{5}\)-\(\left(\dfrac{1}{10}-x\right)\)=\(\left(\dfrac{-2}{5}-\dfrac{1}{2}\right)^2\)
\(\dfrac{2}{5}\)- \(\left(\dfrac{1}{10}-x\right)\)= \(\dfrac{1}{20}\)
\(\left(\dfrac{1}{10}-x\right)\)= \(\dfrac{2}{5}\)-\(\dfrac{1}{20}\)
\(\left(\dfrac{1}{10}-x\right)\)=\(\dfrac{7}{20}\)
x = \(\dfrac{1}{10}\)-\(\dfrac{7}{20}\)
x = \(\dfrac{-1}{4}\)
Chúc bn học tốt
1: Tính : \(\dfrac{\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7.5^2+512}\) 2 . Tìm x biết :\(\left(5.x+1\right)^2=\dfrac{36}{49}\)
Tính
\(a.\left(\dfrac{3}{7}+\dfrac{1}{2}\right)^2;b.\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2;c.\dfrac{5^4.20^4}{25^5.4^5};c.\left(\dfrac{-10}{3}\right)^5.\left(\dfrac{-6}{5}\right)^4\)
BT4:Tìm x, biết:
a) \(x\div\left(\dfrac{3}{4}\right)^3=\left(\dfrac{3}{4}\right)^2\)
b) \(\left(\dfrac{2}{5}\right)^5\div x=\left(\dfrac{2}{5}\right)^8\)
\(\left(-\dfrac{1}{3}\right).\left(\dfrac{1}{3}\right)+\left(\dfrac{15}{2}\right)^7:\left(\dfrac{15}{2}\right)^5-\left(\left(-2\right)^2\right)^3\)
Tìm x, biết:
a) x : \(\left(\dfrac{3}{4}\right)^3\)= \(\left(\dfrac{3}{4}\right)^2\) b) \(\left(\dfrac{2}{5}\right)^5\). x = \(\left(\dfrac{2}{5}\right)^8\)
Trong vở bài tập của bạn Dũng có bài làm sau :
a) \(\left(-5\right)^2.\left(-5\right)^3=\left(-5\right)^6\)
b) \(\left(0,75\right)^3:0,75=\left(0,75\right)^2\)
c) \(\left(0,2\right)^{10}:\left(0,2\right)^5=\left(0,2\right)^2\)
d) \(\left[\left(-\dfrac{1}{7}\right)^2\right]^4=\left(-\dfrac{1}{7}\right)^6\)
e) \(\dfrac{50^3}{125}=\dfrac{50^3}{5^3}=\left(\dfrac{50}{5}\right)^3=10^3=1000\)
Hãy kiểm tra lại các đáp số và sửa lại chỗ sai (nếu có)
f) \(\dfrac{8^{10}}{4^8}=\left(\dfrac{8}{4}\right)^{10-8}=2^2\)
bài 1: thực hiện phép tính
a)\(\dfrac{2^5.8^4.4^3}{16^6}\)
b) \(\left(\dfrac{3}{5}-\dfrac{3}{4}\right).\left(\dfrac{2}{6}-\dfrac{1}{5}\right)^2\)
c)\(3.[\dfrac{-2}{5}]-\left(\dfrac{-1}{2}\right).4:\left(\dfrac{-1}{2}\right)^2\)
Tính :
a) \(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right).\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2\)
b) \(2:\left(\dfrac{1}{2}-\dfrac{2}{3}\right)^3\)
tính
a, \(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right).\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2\)
b,\(2:\left(\dfrac{1}{2}-\dfrac{2}{3}\right)^3\)
