Ta có: \(3\left|2x-3\right|=\left|-10+31\right|\)
\(\Leftrightarrow3\left|2x-3\right|=21\)
\(\Leftrightarrow\left|2x-3\right|=7\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=7\\2x-3=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=10\\2x=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-2\end{matrix}\right.\)
Vậy: \(x\in\left\{5;-2\right\}\)
\(3\left|2x-3\right|=\left|-10+31\right|\)
\(\Rightarrow3\left|2x-3\right|=21\)
\(\Rightarrow\left|2x-3\right|=7\) \(\Rightarrow\left[{}\begin{matrix}2x-3=7\\3-2x=7\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=5\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{5;-2\right\}\)