Sửa đề: 3^x=27
=>3^x=3^3
=>x=3
Sửa đề: 3^x=27
=>3^x=3^3
=>x=3
1. Tìm số nguyên x, y biết:
a) \(^{3^{4-x}}=27\)
b) \(^{3^{-1}}.^{4^x}+3.^{4^x}=\dfrac{5}{3}.^{2^7}\)
(x-1,2)^2=4
(x+1)^3=-125
(x+1,5)^8+(2,7-y)^10=0
3^-1.4^x+ 3.$^x+5/3. 27
9^-x. 27^x= 243
(\(\left(-\dfrac{3}{4}\right)^{3x-1}=-\dfrac{27}{64}\)
Bài 27: Tính
a) \(\left(\dfrac{-1}{3}\right)^4\)
b)\(\left(\dfrac{-9}{4}\right)^3\)
c) \(\left(-0,2\right)^2\)
d) \(\left(-5,3\right)^0\)
\(\dfrac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}\)
\(\dfrac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}\)
\(\dfrac{2^{19}.27^3-15.\left(-4\right)^9.9^4}{6^9.2^{10}+\left(-12\right)^{10}}\)
a, 5^n x 25 = 125^2
b, 3^n x 9^2 = 27^3
c, 2^4 x 4^n = 8^6
Cảm ơn trước ạ!
a)(x+1/3)2=1/4
b)(2.x+3)2=9/121
c)(3.x-1)3= -8/27
d) 4x+4x+2= 112