Question

(\(\left(-\dfrac{3}{4}\right)^{3x-1}=-\dfrac{27}{64}\)

Answer 1

Ta có: \(\left(-\dfrac{3}{4}\right)^{3x-1}=-\dfrac{27}{64}\)

\(\Leftrightarrow\left(-\dfrac{3}{4}\right)^{3x-1}=\left(-\dfrac{3}{4}\right)^3\)

\(\Leftrightarrow3x-1=3\)

\(\Leftrightarrow3x=4\)

hay \(x=\dfrac{4}{3}\)

Vậy: \(x=\dfrac{4}{3}\)

Answer 2

  \(\left(-\dfrac{3}{4}\right)^{3x-1}=-\dfrac{27}{64}\)

  \(\left(-\dfrac{3}{4}\right)^{3x-1}=\left(-\dfrac{3}{4}\right)^3\)

\(\Rightarrow3x-1=3\)

     \(3x=3+1\)

     \(3x=4\)

\(\Rightarrow x=\dfrac{4}{3}\)