\(\dfrac{3}{\sqrt{10}}+\sqrt{40}\)
\(=\dfrac{3\cdot\sqrt{10}}{\sqrt{10}\cdot\sqrt{10}}+\sqrt{2^2\cdot10}\)
\(=\dfrac{3\sqrt{10}}{10}+2\sqrt{10}\)
\(=\dfrac{3\sqrt{10}+2\sqrt{10}\cdot10}{10}\)
\(=\dfrac{3\sqrt{10}+20\sqrt{10}}{10}\)
\(=\dfrac{23\sqrt{10}}{10}\)
\(=\dfrac{3\sqrt{10}}{10}+2\sqrt{10}=2.3\sqrt{10}\)
3/√10 + √40
= 3√10/10 + 2√10
= 3√10/10 + 20√10/10
= 23√10/10