(2x+3)(x+4)-(2 -3x)(x-7)=(2x2+3x+8x+12)-(2x-3x2-14+21x)
= 2x2+3x+8x+12-2x+3x2+14-21x
= 5x2-12x+26
\((2x+3)(x+4)-(2-3x)(x-7)\)
\(=2x^2+8x+3x+12-(2x-14-3x^2+21x)\)
\(=2x^2+11x+12-2x+14+3x^2-21x \)
\(=5x^2-12x+26\)
Ta có: \(\left(2x+3\right)\left(x+4\right)-\left(2-3x\right)\left(x-7\right)\)
\(=2x^2+8x+3x+12-\left(2x-14-3x^2+21x\right)\)
\(=2x^2+11x+12+3x^2-23x+14\)
\(=5x^2-12x+26\)