Question

2x^2+x+10=0

 

Answer 1

\(2\left(x^2+\dfrac{2x}{4}+\dfrac{1}{16}-\dfrac{1}{16}\right)+10=0\)

\(\Leftrightarrow2\left(x+\dfrac{1}{4}\right)^2+\dfrac{79}{8}=0\left(voli\right)\)

Vậy pt vô nghiệm 

Answer 2

\(2x^2+x+10=0\)

\(\Leftrightarrow x^2+x+\dfrac{1}{4}+x^2+\dfrac{39}{4}=0\)

\(\Leftrightarrow\left(x+\dfrac{1}{2}\right)^2+x^2+\dfrac{39}{4}=0\) ( vô lý)

Vậy phương trình vô nghiệm