ta có:
\(\frac{1}{\left(x+2\right)\left(x+3\right)}+\frac{1}{\left(x+3\right)\left(x+4\right)}\)
=\(\frac{1}{x+2}-\frac{1}{x+3}+\frac{1}{x+3}-\frac{1}{x+4}\)
=\(\frac{1}{x+2}-\frac{1}{x+4}\)
=\(\frac{x+4}{\left(x+2\right)\left(x+4\right)}-\frac{x+2}{\left(x+2\right)\left(x+4\right)}\)
\(\frac{2}{\left(x+2\right)\left(x+4\right)}\)