1: \(\Leftrightarrow sinx\cdot\dfrac{1}{2}-\dfrac{\sqrt{3}}{2}\cdot cosx=0\)
=>\(sin\left(x-\dfrac{pi}{3}\right)=0\)
=>x-pi/3=kpi
=>x=kpi+pi/3
3: =>sin 3x*căn 3/2+1/2*cos3x=-1/2
=>sin(3x+pi/6)=-1/2
=>3x+pi/6=-pi/6+k2pi hoặc 3x+pi/6=7/6pi+k2pi
=>3x=-1/3pi+k2pi hoặc 3x=pi+k2pi
=>x=-1/9pi+k2pi/3 hoặc x=pi/3+k2pi/3
2.
\(sinx+cosx=\sqrt{2}sin5x\)
\(\Leftrightarrow\sqrt{2}sin\left(x+\dfrac{\pi}{4}\right)=\sqrt{2}sin5x\)
\(\Leftrightarrow\left[{}\begin{matrix}5x=x+\dfrac{\pi}{4}+k2\pi\\5x=4x-\dfrac{\pi}{4}+k2\pi\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{\pi}{16}+\dfrac{k\pi}{2}\\x=-\dfrac{\pi}{4}+k2\pi\end{matrix}\right.\)