Question

(1-2x)^2=(3x-2)^2

Answer 1

\((1-2x)^2=(3x-2)^2<=> (1-2x)^2-(3x-2)^2<=>(1-2x+3x-2)(1-2x-3x+2)<=>(x-1)(3-5x)\)

Answer 2

(1 - 2x)² = (3x - 2)²

<=> \(\sqrt{\left(1-2x\right)^2}=\sqrt{\left(3x-2\right)^2}\)

<=> 1 - 2x = 3x - 2

<=> 1 + 2 = 3x + 2x

<=> 5x = 3

<=> x = \(\dfrac{3}{5}\)