\(log_{ab^2}x^2=\dfrac{1}{log_{x^2}ab^2}=\dfrac{1}{\dfrac{1}{2}\cdot log_xab^2}\)
\(=\dfrac{1}{\dfrac{1}{2}\cdot\left(log_xa+log_xb^2\right)}\)
\(=\dfrac{2}{log_xa+2\cdot log_xb}=\dfrac{2}{\dfrac{1}{log_ax}+\dfrac{2}{log_bx}}\)
\(=\dfrac{2}{\dfrac{1}{a}+\dfrac{2}{b}}=2:\dfrac{b+2a}{ab}=\dfrac{2ab}{2a+b}\)
=>Chọn D