Question

Answer 1

a: 

\(BC=\sqrt{AB^2+AC^2}=10\left(cm\right)\)

\(AH=\dfrac{AB\cdot AC}{BC}=\dfrac{8\cdot6}{10}=4.8\left(cm\right)\)

BH=AB^2/BC=8^2/10=6,4(cm)

CH=10-6,4=3,6cm

b: \(HM=\dfrac{HA\cdot HB}{AB}=\dfrac{4.8\cdot6.4}{8}=3.84\left(cm\right)\)

\(AM=\dfrac{AH^2}{AB}=\dfrac{4.8^2}{8}=2.88\left(cm\right)\)

BM=8-2,88=5,12(cm)

c: Xét tứ giác AMHN có

góc AMH=góc ANH=góc MAN=90 độ

=>AMHN là hcn

=>AM=HN=2,88cm; AN=HM=3,84cm

CN=6-3,84=2,16(cm)

d: AMHN là hcn

=>AH=MN=4,8cm