2:
a: \(=\dfrac{3-\sqrt{x}}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}=\dfrac{-1}{\sqrt{x}+3}\)
b: \(=\dfrac{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}{\sqrt{x}-3}=\sqrt{x}-2\)
c: \(=6-2x-\left|x-3\right|\)
=6-2x-(3-x)
=6-2x-3+x
=3-x
3:
a: =>|x-3|=3-x
=>x-3<=0
=>x<=3
b: =>|2x-5|=5-2x
=>2x-5<=0
=>x<=5/2
c: =>|x-1/4|=1/4-x
=>x-1/4<=0
=>x<=1/4
