do DE//BC => DE/BC = AD/AB <=> 3/7,5 = 2/(2+x)
=> 2+x = 5 => x = 3
Theo định lý Talet: `(AD)/(AB) = (DE)/(BC)`.
`<=> 2/(2+x) = 3/(7,5)`
`<=> 15= 6 + 3x`
`<=> x = 3`.
\(\text{Xét }\Delta ABC\text{ có:}\)
\(DE//BC\left(gt\right)\)
\(\Rightarrow\dfrac{DE}{BC}=\dfrac{AD}{AB}\left(\text{định lí Ta-lét}\right)\)
\(\Rightarrow\dfrac{3}{7,5}=\dfrac{2}{2+x}\)
\(\Rightarrow2+x=\dfrac{7,5.2}{3}=5\)
\(\Rightarrow x=5-2=3\Rightarrow DB=3\left(cm\right)\)
