Question

Answer 1

c: \(=\dfrac{x^2-3x+3x-16}{x-4}=\dfrac{x^2-16}{x-4}=x+4\)

d: \(\dfrac{4x^2-1+1-4x+4x^2}{2x\left(2x-1\right)}=\dfrac{4x^2}{2x\left(2x-1\right)}=\dfrac{2x}{2x-1}\)

e: \(=\dfrac{2}{x+2}-\dfrac{8}{\left(x+2\right)\left(x-2\right)}+\dfrac{2}{x-2}\)

\(=\dfrac{2x-4-8+2x+4}{\left(x-2\right)\left(x+2\right)}=\dfrac{4x-8}{\left(x-2\right)\left(x+2\right)}=\dfrac{4}{x+2}\)