Question

Answer 1

a: =>(x-2010)(x-1)=0

=>x=2010 hoặc x=1

b: =>(2x-1-x-3)(2x-1+x+3)=0

=>(x-4)(3x+2)=0

=>x=-2/3 hoặc x=4 

Answer 2

a)

\(x\left(x-2010\right)-x+2010=0< =>x\left(x-2010\right)-\left(x-2010\right)=0< =>\left(x-1\right)\left(x-2010\right)=0< =>\left[{}\begin{matrix}x-1=0\\x-2010=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=1\\x=2010\end{matrix}\right.\)b)

\(\left(2x-1\right)^2-\left(x+3\right)^2=0\)

\(\left(2x-1-x-3\right)\left(2x-1+x+3\right)=0\)

\(\left(x-4\right)\left(3x+2\right)=0< =>\left[{}\begin{matrix}x-4=0\\3x+2=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=4\\x=-\dfrac{2}{3}\end{matrix}\right.\)