Question

Answer 1

\(=6\sqrt{3}-12\sqrt{3}+20\sqrt{3}=14\sqrt{3}\)

Answer 2

\(3\sqrt{12}-4\sqrt{27}+5\sqrt{48}\)

= \(3\sqrt{4\cdot3}-4\sqrt{9\cdot3}+5\sqrt{16\cdot3}\)

=\(3\cdot2\cdot\sqrt{3}-4\cdot3\cdot\sqrt{3}+5\cdot4\cdot\sqrt{3}\)

=\(6\sqrt{3}-12\sqrt{3}+20\sqrt{3}=14\sqrt{3}\)

Answer 3

6√3−12√3+20√3=14√3