\(\dfrac{x-3}{6}+\dfrac{x+2}{4}=\dfrac{x-5}{3}+1\\ \Leftrightarrow\dfrac{2\left(x-3\right)}{12}+\dfrac{3\left(x+2\right)}{12}-\dfrac{4\left(x-5\right)}{12}+\dfrac{12}{12}\\ \Leftrightarrow2x-6+3x+6-4x+20+12=0\\ \Leftrightarrow x+32=0\\ \Leftrightarrow x=-32\)
\(\Leftrightarrow2\left(x-3\right)+3\left(x+2\right)=4\left(x-5\right)+12\)
=>2x-6+3x+6=4x-20+12
=>5x=4x-8
=>x=-8
\(\dfrac{x-3}{6}+\dfrac{x+2}{4}=\dfrac{x-5}{3}+1\)
\(\Leftrightarrow\dfrac{2\left(x-3\right)+3\left(x+2\right)}{12}=\dfrac{4\left(x-5\right)+12}{12}\)
\(\Rightarrow2x-6+3x+6=4x-20+12\)
\(\Leftrightarrow2x+3x-4x=6-6-20+12\)
\(\Leftrightarrow x=-8\)
Vậy...
\(\dfrac{x-3}{6}+\dfrac{x+2}{4}=\dfrac{x-5}{3}+1\\ \Leftrightarrow\dfrac{2\left(x-3\right)}{12}+\dfrac{3\left(x+2\right)}{12}-\dfrac{4\left(x-5\right)}{12}-\dfrac{12}{12}=0\\ \Leftrightarrow2x-6+3x+6-4x+20-12=0\\ \Leftrightarrow x+8=0\\ \Leftrightarrow x=-8\)
