Ta có: \(\frac{x+4}{5}-x+4=\frac{x}{3}-\frac{x-2}{2}\)
\(\Leftrightarrow\frac{x+4}{5}-x+4-\frac{x}{3}+\frac{x-2}{2}=0\)
\(\Leftrightarrow\frac{6\left(x+4\right)}{30}-\frac{30x}{30}+\frac{120}{30}-\frac{10x}{30}+\frac{15\left(x-2\right)}{30}=0\)
\(\Leftrightarrow6x+24-30x+120-10x+15x-30=0\)
\(\Leftrightarrow-19x+114=0\)
\(\Leftrightarrow-19x=-114\)
\(\Leftrightarrow x=6\)