Bài 2:
a: \(\Leftrightarrow12\left(x-3\right)+8\left(x+3\right)+6\left(x+4\right)=28\)
=>12x-36+8x+24+6x+24=28
=>26x+12=28
=>26x=16
hay x=8/13
b: \(\Leftrightarrow42\left(x-1\right)-15\left(x+2\right)=10\left(x+1\right)\)
=>42x-42-15x-30=10x+10
=>17x=10+30+42=82
hay x=82/17
c: \(\Leftrightarrow2\left(4x-1\right)-3\left(x+2\right)=11\)
=>8x-2-3x-3=11
=>5x=16
hay x=16/5
Bài 3:
Thay x=1 vào pt, ta được:
\(m^2-1=3\left(m-1\right)\)
=>(m-1)(m-4)=0
=>m=1 hoặc m=4
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