Question

Answer 1

\(a,\dfrac{3}{4}+x=\dfrac{3}{20}\\ \Rightarrow x=-\dfrac{3}{5}\\ b,\dfrac{2}{3}-\left(3x+1\right)=\dfrac{5}{6}\\ \Rightarrow3x+1=-\dfrac{1}{6}\\ \Rightarrow3x=-\dfrac{7}{6}\\ \Rightarrow x=-\dfrac{7}{18}\\ c,\left|x-2\right|-\dfrac{3}{12}=\left(-\dfrac{1}{2}\right)^2\\ \Rightarrow\left|x-2\right|-\dfrac{3}{12}=\dfrac{1}{4}\\ \Rightarrow\left|x-2\right|=\dfrac{1}{2}\\ \Rightarrow\left[{}\begin{matrix}x-2=\dfrac{1}{2}\\x-2=-\dfrac{1}{2}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=\dfrac{3}{2}\end{matrix}\right.\)