Question

Answer 1

Hình vẽ:

Answer 2

\(BC=24,3\left(cm\right)\)

Answer 3

Lời giải:
Ta có:

$\frac{AC}{BC}=\sin B\Rightarrow BC=\frac{AC}{\sin B}=\frac{12}{\sin 27^0}=26,4$ (cm)

$\frac{AC}{AB}=\tan B\Rightarrow AB=\frac{AC}{\tan B}=\frac{12}{\tan 27^0}=23,6$ (cm)

$\frac{AH}{AB}=\sin B\Rightarrow AH=AB\sin B=23,6\sin 12^0=4,9$ (cm)

$\frac{BH}{AB}=\cos B\Rightarrow BH=\AB\cos B=23,6.\cos 12^0=23,1$ (cm)

$CH=BC-BH=26,4-23,1=3,3$ (cm)