Question

Answer 1

\(15x=10y=6z\Rightarrow\dfrac{x}{\dfrac{1}{15}}=\dfrac{y}{\dfrac{1}{10}}=\dfrac{z}{\dfrac{1}{6}}\)

Áp dụng TCDTSBN ta có:

\(\dfrac{x}{\dfrac{1}{15}}=\dfrac{y}{\dfrac{1}{10}}=\dfrac{z}{\dfrac{1}{6}}=\dfrac{x+y+z}{\dfrac{1}{15}+\dfrac{1}{10}+\dfrac{1}{6}}=-\dfrac{40}{\dfrac{1}{3}}=-120\)

\(\dfrac{x}{\dfrac{1}{15}}=-120\Rightarrow x=-8\\ \dfrac{y}{\dfrac{1}{10}}=-120\Rightarrow y=-12\\ \dfrac{z}{\dfrac{1}{6}}=-120\Rightarrow z=-20\)