\(2^{x-2}-3\cdot2^x=-88\)
\(\Leftrightarrow2^x\cdot\dfrac{1}{4}-3\cdot2^x=-88\)
\(\Leftrightarrow2^x=88:\dfrac{11}{4}=88\cdot\dfrac{4}{11}=32\)
hay x=5
\(\dfrac{x+7}{x-4}=\dfrac{25}{14}\)
\(\Leftrightarrow25x-100=14x+98\)
hay x=18
Vậy: \(x_1+x_2=23\)




