\(a,\Rightarrow\left|x+1\right|=\dfrac{2}{5}\Rightarrow\left[{}\begin{matrix}x+1=\dfrac{2}{5}\\x+1=-\dfrac{2}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\dfrac{3}{5}\\x=-\dfrac{7}{5}\end{matrix}\right.\\ b,\Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{3}=\dfrac{1}{3}\\\dfrac{1}{3}-x=\dfrac{1}{3}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=0\end{matrix}\right.\)
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