\(\left(2x+\dfrac{1}{2}\right)^2=\dfrac{1}{4}\\ \Rightarrow\left[{}\begin{matrix}2x+\dfrac{1}{2}=-\dfrac{1}{2}\\2x+\dfrac{1}{2}=\dfrac{1}{2}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=-1\\2x=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=0\end{matrix}\right.\)
\(\left(2x+\dfrac{1}{2}\right)^2-\left(\dfrac{1}{2}\right)^2=0\)
\(\left(2x+\dfrac{1}{2}-\dfrac{1}{2}\right)\left(2x+\dfrac{1}{2}+\dfrac{1}{2}\right)=0\)
\(2x\left(2x+1\right)=0\)
\(\left[{}\begin{matrix}2x=0\\2x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{1}{2}\end{matrix}\right.\)
