Question

Answer 1

a: Ta có: \(\widehat{BAH}+\widehat{B}=90^0\)

\(\widehat{ACB}+\widehat{B}=90^0\)

Do đó: \(\widehat{BAH}=\widehat{ACB}\)

b: Ta có: \(\widehat{CAD}+\widehat{BAD}=90^0\)

\(\widehat{CDA}+\widehat{HAD}=90^0\)

mà \(\widehat{BAD}=\widehat{HAD}\)

nên \(\widehat{CAD}=\widehat{CDA}\)