Question

Answer 1

\(\Leftrightarrow\left|\dfrac{1}{2}x-2\right|=\left|x+\dfrac{2}{3}\right|\\ \Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-2=x+\dfrac{2}{3}\\2-\dfrac{1}{2}x=x+\dfrac{2}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x=-\dfrac{8}{3}\\\dfrac{1}{2}x=-\dfrac{4}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{16}{3}\\x=-\dfrac{8}{3}\end{matrix}\right.\)