Question

Answer 1

a: Ta có: \(\left|x+3.2\right|-1=-5\)

\(\Leftrightarrow\left|x+3.2\right|=-4\)(vô lý)

b: Ta có: \(24:\left|\dfrac{1}{2}-x\right|=6\)

\(\Leftrightarrow\left|x-\dfrac{1}{2}\right|=4\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=4\\x-\dfrac{1}{2}=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{9}{2}\\x=-\dfrac{7}{2}\end{matrix}\right.\)

Answer 2

a) ta có: |x+3,2|-1=-5

\(\Leftrightarrow\)|x+3.2| = -4 < vô lý >

\(\Rightarrow\) Không có giá trị của x.