Cho a,b,c>0.Tìm Max:

\(A=\sqrt{\frac{2a}{a+b}}+\sqrt{\frac{2b}{b+c}}+\sqrt{\frac{2c}{c+a}}\)

Cho x,y,z>0 thỏa xy+yz+zx=1.Chứng minh rằng:

\(\Sigma\frac{1}{xy}\ge3+\Sigma\frac{\sqrt{x^2+1}}{x}\)

\(\text{Cho x,y}\in R\text{ thỏa mãn }x^2+y^2=4.\text{Tìm Max}\)

\(A=\frac{xy}{x+y+2}\)

\(\text{Cho x,y thuộc R thỏa mãn }x^2+y^2=4.\text{Tìm Max:} \)

\(A=\frac{xy}{x+y+2}\)

\(\)\(Cho\text{ }x,y\in R\text{ }thỏa\text{ }x^2+y^2=4.\text{Tìm Min}\)

\(A=\frac{xy}{x+y+1}\)