\(N = \frac{-7 \cdot 10}{10^{2006}} + \frac{-15}{10^{2006}}\)

\(N = \frac{-70 - 15}{10^{2006}}\)

\(N = \frac{-85}{10^{2006}}\)

\(M = \frac{-15 \cdot 10}{10^{2006}} + \frac{-7}{10^{2006}}\)

\(M = \frac{-150 - 7}{10^{2006}}\)

\(M = \frac{-157}{10^{2006}}\)

vì -85 > -157 nên \(\frac{-85}{10^{2006}} > \frac{-157}{10^{2006}}\)

⇒ N > M

\(44 \times y = 11\)

\(y = \frac{11}{44}\)

\(y = \frac{1}{4}\)

\(x - \left(-\frac{3}{5}\right) = -\frac{5}{3}\)

\(x + \frac{3}{5} = -\frac{5}{3}\)

\(x = -\frac{5}{3} - \frac{3}{5}\)

\(x = -\frac{25}{15} - \frac{9}{15}\)

\(x = -\frac{34}{15}\)