a và c

ũa seo cảm mơn có 1 ng zị ?:)

\(=\dfrac{3131:101}{4545:101}=\dfrac{31}{45}\)

a.\(ĐK:x\ne-2\)

\(\Leftrightarrow\dfrac{2x-1}{x+2}=\dfrac{\left(x+2\right)-x}{x-2}\)

\(\Leftrightarrow2x-1=2\)

\(\Leftrightarrow2x=3\)

\(\Leftrightarrow x=\dfrac{3}{2}\left(tm\right)\)

b.\(ĐK:x\ne\pm2\)

\(\Leftrightarrow\dfrac{10}{x+2}=\dfrac{\left(x-2\right)+1}{x-2}\)

\(\Leftrightarrow10=x-1\)

\(\Leftrightarrow x=11\left(tm\right)\)

c.\(ĐK:x\ne\pm1\)

\(\Leftrightarrow\dfrac{16}{\left(x-1\right)\left(x+1\right)}=\dfrac{5}{x+1}+\dfrac{2\left(x-3\right)}{x-1}\)

\(\Leftrightarrow\dfrac{16}{\left(x-1\right)\left(x+1\right)}=\dfrac{5\left(x-1\right)+\left(2x+6\right)\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}\)

\(\Leftrightarrow16=5x-5+2x^2+2x+6x+6\)

\(\Leftrightarrow2x^2+13x-17=0\)

d.\(x\ne\pm2;x\ne-1\)

\(\Leftrightarrow\dfrac{x^2-6}{\left(x+1\right)\left(x+2\right)}=1-\dfrac{x}{x+2}\)

\(\Leftrightarrow\dfrac{x^2-6}{\left(x+1\right)\left(x+2\right)}=\dfrac{\left(x+1\right)\left(x+2\right)-x\left(x+1\right)}{\left(x+1\right)\left(x+2\right)}\)

\(\Leftrightarrow x^2-6=x^2+2x+x+2-x^2-x\)

\(\Leftrightarrow x^2-2x-8=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\left(tm\right)\\x=-2\left(ktm\right)\end{matrix}\right.\)

câu b sai nha pạn