\(x^2+2x-3=0\)
\(x^2+3x-x-3=0\)
\(x\left(x-1\right)+3\left(x-1\right)=0\)
\(\left(x+3\right)\left(x-1\right)=0\)
\(\left[{}\begin{matrix}x+3=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=1\end{matrix}\right.\)
\(\Rightarrow x=3\) hoặc \(x+2=3\)
\(\Rightarrow x=3\) hoặc \(x=1\)
Vậy x \(\in\left\{3;1\right\}\)
\(x\left(x+2\right)=3\)
\(\Leftrightarrow x^2+2x-3=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=1\end{matrix}\right.\)