\(\left(x+\dfrac{3}{2}\right)^2=\dfrac{9}{49}\)
\(\left(x+\dfrac{3}{2}\right)^2=\left(\pm\dfrac{3}{7}\right)^2\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{3}{2}=\dfrac{3}{7}\\x+\dfrac{3}{2}=\dfrac{-3}{7}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-15}{14}\\x=\dfrac{-27}{14}\end{matrix}\right.\)
Vậy \(x=\dfrac{-15}{14}\) hoặc \(x=\dfrac{-27}{14}\) thỏa mãn .
tik mik nha !!!
\(\left(x+\dfrac{3}{2}\right)^2=\left(\dfrac{3}{7}\right)^2\Leftrightarrow x+\dfrac{3}{2}=\dfrac{3}{7}\Leftrightarrow x=\dfrac{-15}{14}\)